Question

A system initially has a pressure of 12 atm and a volume of 9 L. What is the volume if the pressure is decreased to 6 atm?

Answer 1

The answer is 18 L

Step-by-step explanation:

In order to find the volume , we use the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

`V_2 = (P_1V_1)/(P_2) \\`

From the question

P1 = 12 atm

V1 = 9 L

P2 = 6 atm

We have

`V_2 = (12 * 9)/(6) = (108)/(6) \\`

We have the final answer as

18 L

Hope this helps you