Answer:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O
Step-by-step explanation:
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 1NaC₂H₃O₂
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂
(on the reactant side there are two molecules of C₂H₃O₂ and 2 atoms of Na, so in order to balance that we put the coefficient 2 on NAC₂H₃O₂)
So the final product is
1Na₂S + 1Cd(C₂H₃O₂)₂ → 1CdS + 2NaC₂H₃O₂