Question

A ball is dropped from a height of 100 cm. The rebound heights to the nearest centimeter are 60, 36, 22, .... What is the total distance the ball will travel both up an down?

Answer 1

400 cm

Explanation:

Given that:

Initial height at which ball was dropped = 100m

Rebound heights to the nearest cm = 60, 36, 22...

First we find the rebound percentage x;

x% * 100m = 60

100x % = 60

x = 60%

Hemce, we need to calculate the rebound velocities which aren't given:

0.6 * 22 = 13.2 = 13cm

0.6 * 13 = 7.8 = 8cm

0.6 * 8 = 4.8 = 5cm

0.6 * 5 = 3cm

0. 6 * 3 = 1.8 = 2 cm

0.6 * 2 = 1.2 = 1cm

The total distance the ball travels UP and DOWN :

(100 + 2(60) + 2(36) + 2(22) + 2(13) + 2(8) + 2(5) + 2(3) + 2(2) + 2(1))

= 400 cm