Question

`\huge\boxed{PLEASE\;HELP!}`

Answer 1

`\boxed{y = - 1x + 2}.`

Explanation:

`in \: order \: to \: solve \: the \: problem \: we \: invoke \\ \: the \:slope \: intercept \: form : \\ y = mx + c \\ lets \: get \: m \to \: \\ m= ( y_(2) - y_(1) )/(x_(2) -x_(1) ) = (2 - 0)/(0 - ( - 2)) \\ m = \boxed{- 1}. \\to \: find \: c \: we : apply \to \\ y = mx + c...... \\ using \: any \: pair \: we \: can \: get \: c. \\ c = y - mx \\ c =2 - 1(0) \\ c = \boxed{2}. \\ hence \: the \: required \: equation \: is : \\ \boxed{y = - 1x + 2}.`

♨Rage♨

Answer 2

y=1x+2

Explanation:

do
`y2-y1 / x2-x1` to get m(slope)

y1=2

x1=0

y2=0

x2=-2

then do y=mx+b

1=m(slope)

2=b(y-intercept)

Hope this wasn't to confusing!

I hope this helps! :)