Question

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3). What is the coordinates of the image if the parallelogram is dilated with a scale factor of -1/3

Answer 1

Answer:
`(\frac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .`

Explanation:

Transformation rule for dilation:

`(x,y)\to(kx,ky)` , where k = scale factor

Given : Scale factor =
`-\frac13`

Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)

Vertices after dilation:

`(-1,6)\to(-1*(-1)/(3),6*(-1)/(3))=(\frac13,-2)`

`(0,9)*(0*-\frac13,9*-\frac13)=(0,-3)`

`(6,-3)\to(6*-\frac13,\ -3*-\frac13)=(-2,1)`

`(3,-3)\to (3*-\frac13,\ -3*-\frac13)=(-1,1)`

Hence, the coordinates of the image if the parallelogram =
`(\frac13,-2),\ (0,-3),\ (-2,1),\ (-1,1) .`