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How many moles are in 843 grams of MgCl2
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How many moles are in 843 grams of MgCl2

User Nikhilesh
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2 Answers

7 votes
n=m/M
We have m[MgCl2]=843g, M[MgCl2]=95g/mol
So n[MgCl2]= 843/95=8.87mol
User Ceteras
by
3.0k points
7 votes

Answer:

moles = mass / Molar mass

  • Mass = 843
  • molar mass = 95.211

moles -> 843/95.211 = 8.85 mol

User Silverio
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3.4k points
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