Question

24. Janet and Jack are walking in a two-day event to raise money for charity.

Janet asks a friend for a $7.50 donation, plus $0.10 for each mile she
walks. Jack asks a friend for a $5.50 donation, plus $0.15 for each mile
he walks. At how many miles of walking would Janet and Jack collect the
same amount of money?

Answer 1

40 miles walk

Explanation:

Let the miles walked by both of them be x at which money collected by same

for Janet

Fixed donation asked = $7.50

money asked for walking 1 mile = $0.10

money made by Janet if he walks x miles = x*$0.10 = $0.10x

Total money collected by Janet = Fixed donation asked + money made by Janet if he walks x miles

Total money collected by Janet =7.50 + 0.10x

For Jack

Fixed donation asked = $5.50

money asked for walking 1 mile = $0.15

money made by Janet if he walks x miles = x*$0.15 = $0.15x

Total money collected by Jack = Fixed donation asked + money made by Jack if he walks x miles

Total money collected by Jack =5.50 + 0.15x

we have to find miles at which money collected by both of them be same

and we have decided that it it as x mile walk then

Total money collected by Janet = Total money collected by Jack

7.50 + 0.10x = 5.50 + 0.15x

=> 7.50 - 5.50 = 0.15x - 0.10x

=> 2 = 0.05x

=> x = 2/0.05 = 40

Thus, at 40 miles walk money collected by both of them will be same