Question

Write an equation of the line in STANDARD FORM with a slope of 3 and passes through the point (6,-2) in standard form using the formula

y-y1 = m (x-x1) please!

Answer 1

The formula has been given already, just substitute the values.

m is the slope = 3

y1 = -2

x1 = 6

y - (-2) = m (x - (6))

y + 2 = 3(x - 6)