Question

Use the elimination method to find each pair of simultaneous equation

10a -2b= 30
3a - 2b=2
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Answer 1

solutions are a=4 b=5

Explanation:

10a– 2b=30

3a- 2b=2

Multiply 10a 2b = 30 by 3: 30a – 6b – 90

Multiply 3a – 2b =2 by 10: 30a - 20b = 20

[30a – 6b = 90]

[30a – 20b = 20]

Subtract the equations

30a – 20b = 20

-

30a- 6b= 90

______________

-14b = -70

[30a -6b = 90]

[-14b = -70]

Solve - 14b = -70 for b: b=5

For 30a - 6b = 90 plug in b=5

Solve 30a –6· 5 = 90 for a: a= 4

The solutions to the system of equations are:

a=4 b=5

Answer 2

Here is the solution....hope it helps:)