Answer:
The liquid can be identified
Step-by-step explanation:
Given that density is defined as mass per unit volume.
We have the following information regarding the unknown liquid;
Mass= 1.40 kg = 1400 g
Volume = 1378 cm^3 = 1378 ml
Density of unknown liquid = 1400/1378 = 1.012 g/ml this is approximately 1.0 g/ml
It is possible to identify the liquid, the liquid is ethanolamine