Question

Which values from this set {−36, −32, −16, 0, 4, 16} satisfy this inequality? −14x+6≥14 −32, −16, 0, 4, and 16 only 0, 4, and 16 only −36, −32, and −16 only −36 and −32 onlyWhich values from this set {−36, −32, −16, 0, 4, 16} satisfy this inequality? −14x+6≥14 −32, −16, 0, 4, and 16 only 0, 4, and 16 only −36, −32, and −16 only −36 and −32 only

Answer 1

Explanation:

Given the inequality −14x+6≥14, we are to find the range of x that will make the inequality true.

Given −14x+6≥14

Subtract 6 from both sides.

−14x+6-6≥14-6

-14x≥8

-7x≥4

Multiply both sides by -1

-(-7)x≤-4

7x ≤ -4

x≤-4/7

This shows that the values of x is always less than or equal to -0.57

Hence the values less tan the value of x in the inequality are -36, -32 and -16