Question

Calculate the maximum mass of potassium sulfate, K2SO4, that could be formed when 4.9 g of sulfuric acid reacts with excess potassium hydroxide.

H2SO4 + 2KOH → K2SO4 + 2H2O

Answer 1

From 4.9 g of sulfuric acid 8.175 g of potassium sulfate is formed.

Step-by-step explanation:

Given data:

Mass of H₂SO₄ = 4.9 g

Mass of K₂SO₄ formed = ?

Solution:

Chemical reaction:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

Number of moles of H₂SO₄:

Number of moles = mass/ molar mass

Number of moles = 4.9 g/ 98.1 g/mol

Number of moles = 0.05 mol

Now we will compare the moles of H₂SO₄ with K₂SO₄ .

H₂SO₄ : K₂SO₄

1 : 1

0.05 : 0.05

Mass of K₂SO₄:

Mass = number of moles × molar mass

Mass = 0.05 mol × 174.3 g/mol

Mass = 8.715 g

Thus, from 4.9 g of sulfuric acid 8.175 g of potassium sulfate is formed.