Question

Find the LCM of x2 + x,x2-1,x2-x

Answer 1

`first \: \\ x {}^(2) + x \\ = x(x + 1) \\ \\ second \\ {x}^(2) - 1 \\ = (x) {}^(2) - (1) { }^(2) \\ = (x + 1)(x - 1) \\ \\ third \\ x {}^(2) - x \\ = x(x - 1) \\ \\ therefore \: \: lcm = x(x + 1)(x - 1)`

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