Answer:
12 cm ×5cm
Explanation:
To find the dimensions of the airplane ticket, let's assume that the airplane ticket is a rectangle.
Area of rectangle= length ×width
Perimeter of rectangle= 2(length +width)
Let the length and width of the plane ticket be L and W cm respectively.
From the area of the ticket,
LW= 60 -----(1)
From the perimeter of the ticket,
2(L +W)= 34
Divide both sides by 2:
L +W= 17 -----(2)
Let's solve the equations by substitution.
From (2):
L= 17 -W -----(3)
Substitute (3) into (1):
(17 -W)(W)= 60
17W -W²= 60
W² -17W +60= 0
Factorise:
(W -5)(W -12)= 0
W -5= 0 or W -12= 0
W= 5 or W= 12
Substitute into (3):
L= 17 -5 or L= 17 -12
L= 12 or L= 5
Thus, the dimensions of the ticket is 12 cm ×5 cm.