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Write the equation of a line through the point (6, 2) and
perpendicualr to y = 3x + 8.

Write the equation of a line through the point (6, 2) and perpendicualr to y = 3x-example-1
User Nunaxe
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1 Answer

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the correct answer is y - 2 = -1/3(x - 6)

you would use the equation y - y^1 = m(x - x^1) and plug in the point (6,2) for x^1 and y^1. then find the opposite reciprocal of the slope, which would be -1/3 (in perpendicular lines, the slope is always the opposite reciprocal of the other), and plug that in for m. after that, you have your answer! hope this helps, good luck!
User Nhan Cao
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