Question

A line passes through (-2, 5) and has a slope of what is the equation of the line in point-slope form?

y+ 2 = } (x - 5)
A.
B.
y-5= (x + 2)
O C. y= {x +
3
o
D.
y+5 = (– 2)

Answer 1

it actually y=1/3x+17/3

Explanation:

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was 1/3. So you can right away fill in the equation for a line somewhat to read:

y=1/3x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-2,5). When x of the line is -2, y of the line must be 5.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the 1/3 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-2,5).

So, why not plug in for x the number -2 and for y the number 5? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-2,5). y=mx+b or 5=1/3 × -2+b, or solving for b: b=5-(1/3)(-2). b=17/3.

The equation of the line that passes through the point (-2,5) with a slope of 1/3

is

y=1/3x+17/3

There's your explanation

Answer 2

y-5=m(x+2) is the answer in point slope form