Question

PLEASE HELP

To celebrate a victory, a pitcher throws her glove straight up into the air with an initial velocity of 6.0 m/s. What is the maximum height of the glove? (Show work)

Answer 1

h = 1.8 m

Step-by-step explanation:

The initial velocity of the glove, u =- 6 m/s

We need to find the maximum height of the glove. Let it is equal to h. Using equation of kinematics. At the maximum height v = 0

`v^2-u^2=2ah`, h is the maximum height and a = -g

`0^2-(6)^2=2* (-10)* h\\\\h=(36)/(20)\\\\h=1.8\ m`

Hence, it will go up to a height of 1.8 m.