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42 votes
42 votes
F(t)=0.25t
x^(2)-1.5t+2.5 the average rate of change of f(t) from t=5 to t=8

User Afrischke
by
2.8k points

2 Answers

6 votes
6 votes

Answer:

1.75

Explanation:


m=(f(b)-f(a))/(b-a)


m=(f(8)-f(5))/(8-5)


m=(6.5-1.25)/(3)


m=(5.25)/(3)


m=1.75

Therefore, the average rate of change of f(t) from t=5 to t=8 is 1.75

User Michael Aigner
by
3.2k points
25 votes
25 votes

Answer:

(x)(x)

Explanation:

User Steve Graham
by
2.8k points