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A bicycle and its rider have a combined mass of 80. kilograms and a speed of 6.0 meters per second. what is the magnitude of the average force needed to bring the bicycle and its rider to a stop in 4.0 seconds?

User Koushik Das
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2 Answers

16 votes
16 votes

Final answer:

The magnitude of the average force needed to stop a bicycle and its rider with a mass of 80 kilograms moving at 6.0 meters per second in 4.0 seconds is 120 newtons.

Step-by-step explanation:

The question asks for the magnitude of the average force required to bring a bicycle and its rider with a combined mass of 80 kilograms, moving at a speed of 6.0 meters per second, to a stop in 4.0 seconds. To find this, we use the formula for force based on Newton's second law of motion, F = ma, where F is force, m is mass, and a is acceleration.

First, we calculate the acceleration needed to stop the bicycle in the given time. Since the final velocity is 0 m/s (because the bicycle stops), we can calculate acceleration as a = (Vf - Vi) / t, where Vf is final velocity, Vi is initial velocity, and t is time. Substituting the given values:

a = (0 m/s - 6.0 m/s) / 4.0 s = -1.5 m/s². The negative sign indicates that the acceleration is in the opposite direction of the initial velocity (deceleration).

Now, applying this acceleration to the formula for force, we get: F = m * a = 80 kg * (-1.5 m/s²) = -120 N. The magnitude of this force is 120 newtons; the negative sign is omitted when considering magnitude.

User Liam Galvin
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2.6k points
22 votes
22 votes

Answer:

120 N

Step-by-step explanation:

Use the equation F = m(Vf–Vi) / Δt.

average force = mass (final velocity - initial velocity) / change in time

F = 80. kg(6.0 m/s) / 4 s = 480 / 4 = 120 kgm / s^2 = 120 Newtons

User Mateo Tibaquira
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3.1k points