Question

What is the rate of acceleration of a hammer whose head goes from moving -2 m/s (downward) to +0.5 m/s (upward) when it hits and bounces off a hard rock ? The actual bounce takes 0.025 seconds

Answer 1

`a=100\ m/s^2`

Step-by-step explanation:

Given that,

Initial velocity, u = -2 m/s

Final velocity, v = =.5 m/s

Time, t = 0.025 s

We need to find the rate of acceleration of a hammer. Acceleration is equal to the change in velocity divided by the time taken.

`a=(v-u)/(t)\\\\a=(0.5-(-2))/(0.025)\\\\a=100\ m/s^2`

So, the acceleration of the jet is
`100\ m/s^2`.