Question

Evaluate h(x)=-2x+9 when x=-2,0, and 5 .

h(-2)=

h(0)=

h(5)=

Answer 1

h(-2) = 13

h(0) = 9

h(5) = -1

Explanation:

Plug in each value of x into the h(x) equation and solve.

h(-2) = -2(-2)+9

h(-2) = 4+9

h(-2) = 13

h(0) = -2(0)+9

h(0) = 9

h(5) = -2(5)+9

h(5) = -10+9

h(5) = -1

Answer 2

h(-2)=2×(-2)+9

= -4+9

=-5

h(0)=2×0+9

=0+9

=9

h(5)=2×5+9

=10+9

=19

Explanation:

Hope it helps