Question

A boy pushes a box with a force of 150 N at an angle of 40 with a flat floor. What component of his force is directed downward , or into the floor . PLEASE ANSWER!!!!!

Answer 1

`F_y=96.4N`

Step-by-step explanation:

Hello.

In this case, considering the force diagram shown on the attached picture, we can see that the component of his force is directed downwards is:

`F_y=F* sin (\theta)`

Because the other component is the horizontal one:

`F_x=F* cos(\theta)`

In this case, the y-component force turns out:

`F_y=150N* sin (40\°)\\\\F_y=96.4N`

Moreover, the x-component force is also computed if required:

`F_x=150N* cos(40\°)\\\\F_x=114.9N`

Best regards.