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Which transformation of AB will produce a line segment A'B' that is parallel to AB?

1 Answer

7 votes

Options:

Rotation of 180° about point B

Rotation of 90° about point b

Reflection over the x-axis

Translation down 2 units

Answer:

Rotation of 180° about point B

Explanation:

Considering coordinates of point B

Assume the coordinates of the line at point B is (x,y)

i.e.
B = (x,y)

First, we need to determine the slope at point B

Taking coordinates about the origin.

The slope of B is:


m = (y_2 - y_1)/(x_2 - x_1)

Where


(x_1,y_1) = (0,0) --- origin


(x_2,y_2) = (x,y)


m = (y_2 - y_1)/(x_2 - x_1) becomes


m = (y - 0)/(x - 0)


m = (y)/(x)

Taking the options one after the other:

Option A.

When rotated by 180°, the resulting coordinates of B would be


B' = (-x,-y)

Taking the slope of B'

The slope of B is:


m = (y_2 - y_1)/(x_2 - x_1)

Where


(x_1,y_1) = (0,0) --- origin


(x_2,y_2) = (-x,-y)


m = (y_2 - y_1)/(x_2 - x_1) becomes


m = (-y - 0)/(-x - 0)


m = (-y)/(-x)


m = (y)/(x)

Notice that the slope of B and B' is the same;


m = (y)/(x)

Hence:

Rotation of 180° about point B answers the question

There's no need to check for other options

User Ziriax
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