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Solve |y + 2| > 6

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User Atli
by
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1 Answer

2 votes

Answer:


\huge\boxed{y>4\ \vee\ y<-8}\\\boxed{y\in(-\infty;\ -8)\ \cup\ (4;\ \infty)}

Explanation:


|y+2|>6\iff y+2>6\ \vee\ y+2<-6\qquad|\text{subtract 2 from both sides}\\\\y+2-2>6-2\ \vee\ y+2-2<-6-2\\\\y>4\ \vee\ y<-8\Rightarrow y\in(-\infty;\ -8)\ \cup\ (4;\ \infty)

User Grant Humphries
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