Question

Find the numerical value of the log expression, please help!

Answer 1

101

Explanation:

`\log a=-8\\\\10^(\log a)=10^(-8)\\\\a=10^(-8)`

`\log b=-9\\\\10^(\log b)=10^(-9)\\\\b=10^(-9)`

`\log c=-9\\\\10^(\log c)=10^(-9)\\\\c=10^(-9)`

`\displaystyle \log(a^2)/(b^5c^8)=\log((10^(-8))^2)/((10^(-9))^5(10^(-9))^8)=\log(10^(-16))/((10^(-9))^(13))=\log(10^(-16))/(10^(-117))=\log(10^(-16-(-117)))=\log(10^(101))=101`