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Find the numerical value of the log expression, please help!

Find the numerical value of the log expression, please help!-example-1
User Garytje
by
8.5k points

1 Answer

8 votes

Answer:

101

Explanation:


\log a=-8\\\\10^(\log a)=10^(-8)\\\\a=10^(-8)


\log b=-9\\\\10^(\log b)=10^(-9)\\\\b=10^(-9)


\log c=-9\\\\10^(\log c)=10^(-9)\\\\c=10^(-9)


\displaystyle \log(a^2)/(b^5c^8)=\log((10^(-8))^2)/((10^(-9))^5(10^(-9))^8)=\log(10^(-16))/((10^(-9))^(13))=\log(10^(-16))/(10^(-117))=\log(10^(-16-(-117)))=\log(10^(101))=101

User Steven Holtzen
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