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A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? 5 6 2 8 5.3A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? 5 6 2 8 5.3

User Leonie
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1 Answer

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Answer:

The order of maximum is
n = 5

Step-by-step explanation:

From the question we are told that

The diffraction grating is k = 300 lines per mm = 300000 lines per m

The wavelength is
\lambda  =  630 \  nm  =  630 *10^(-9) \  m

Generally the condition for constructive interference is mathematically represented as


dsin \theta = n  * \lambda

Here n is the order maximum

d is the distance the grating which is mathematically represented as


d =  (1)/(k)

=>
d =  (1)/(300000)

=>
d =  3.3*10^(-6)\  m

So


n  = (dsin \theta)/( \lambda)

at maximum
sin\theta  =  1


n  = (d)/(\lambda)

=>
n  = (3.3*10^(-6))/(630 *10^(-9))

=>
n = 5

User Fredmaggiowski
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