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3 votes
Complete the square

to find the vertex
of this parabola.
y^2+6y+8x+1=0
([?], [?])

1 Answer

6 votes

Answer:


(1,-3)

Explanation:

Complete the squares


y^2+6y+8x+1=0\\\\y^2+6y=-8x-1\\\\y^2+6y+9=-8x-1+9\\\\(y+3)^2=-8x+8\\\\(y+3)^2=-8(x-1)

We now compare to the equation
(y-k)^2=2p(x-h) where
(h,k) is the vertex of the parabola. Hence, the vertex of the parabola is
(1,-3).

User Evan Rogers
by
7.8k points

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