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TV Cabinet TV screens are measured on the diagonal. If we have a TV-cabinet that is 72 inches long and 64 inches high, how large a TV could we put in the space (leave 2-inches on all sides for the edging of the TV)? Round your answer to the nearest tenth.

User Kinkajou
by
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1 Answer

4 votes

Answer:

94in

Explanation:

We are expected to solve for the diagonal of a rectangular shape.

given that the length, l=72in

width, w=64in

we can apply the Pythagoras theorem to solve for the diagonal since it corresponds to the hypotenuse of the rectangle

note: we are to leave 2-inches on all sides for the edging of the TV

l=72-2= 70 in

w=64-2=62

diag=√l^2+w^2

diag=√70^2+62^2

diag=√4900+3844

diag=√8744

diag=93.50 in

to the nearest tenth, it is 94in

User Ikkez
by
7.9k points
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