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Two observers times the motion of a car from one place to another. The first observer's clock read 262 seconds at the start and 375 seconds at the end of the car's motion. The second observer's clock read -86 seconds at the start. What did it read at the end?

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Answer:

The time of the second observer at the end of the car motion is 27 s

Step-by-step explanation:

Initial time of the first observer, t₁ = 262 s

final time of the first observer, t₂ = 375 s

The time of the car motion, t = t₂ - t₁

t = 375 s - 262 s

t = 113 s

Initial time of the second observer, t₁ = -86 s

final time of the second observer, t₂ = ?

The time of the car motion, t = t₂ - t₁

113 = t₂ - t₁

113 = t₂ - (-86)

113 = t₂ + 86

t₂ = 113 - 86

t₂ = 27 s

Therefore, the time of the second observer at the end of the car motion is 27 s

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