Answer:
The time of the second observer at the end of the car motion is 27 s
Step-by-step explanation:
Initial time of the first observer, t₁ = 262 s
final time of the first observer, t₂ = 375 s
The time of the car motion, t = t₂ - t₁
t = 375 s - 262 s
t = 113 s
Initial time of the second observer, t₁ = -86 s
final time of the second observer, t₂ = ?
The time of the car motion, t = t₂ - t₁
113 = t₂ - t₁
113 = t₂ - (-86)
113 = t₂ + 86
t₂ = 113 - 86
t₂ = 27 s
Therefore, the time of the second observer at the end of the car motion is 27 s