Question

A 2.0 Kg box is being pulled up a ramp with a force of 25.0 Newtons. The ramp has an incline of 30 degrees. If the coefficient of friction is 0.752, find the acceleration of the block up the ramp. You may round your answer to the nearest tenth where necessary!!!

Answer 1

The acceleration of the block is 1.21 m/s².

Step-by-step explanation:

Given that,

Mass = 2.0 kg

Force = 25.0 n

Angle = 30°

Coefficient of friction = 0.752

We need to calculate the acceleration of the block

Using balance equation

`F-(mg\sin\theta+\mu mg\cos\theta)=ma`

Put the value into the formula

`25-(2.0*9.8\sin30+0.752*2.0*9.8\cos30)=2.0a`

`a=(25-(2.0*9.8\sin30+0.752*2.0*9.8\cos30))/(2.0)`

`a=1.21\ m/s^(2)`

Hence, The acceleration of the block is 1.21 m/s².