Question

2. JI. has coordinates J(-6, 1) and Z(-4, 3). Find the coordinates of the midpoint.​

Answer 1

(- 5, 2 )

Explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(
`(x_(1)+x_(2) )/(2)`,
`(y_(1)+y_(2) )/(2)` )

Here (x₁, y₁ ) = (- 6, 1) and (x₂, y₂ ) = (- 4, 3) thus

midpoint =
`(-6-4)/(2)`,
`(1+3)/(2)` ) = (
`(-10)/(2)`,
`(4)/(2)` ) = (- 5, 2 )