Question

Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of itself the result is a 15. The modern day equation that models this problem is x plus StartFraction 1 over 4 EndFraction x equals 15.. What is the solution to the equation? x = 10 x = 12 x = 15 x = 30

Answer 1

B

Explanation:

2020 edge

Answer 2

`x = 12`

Explanation:

x = the quantity to find

This quantity added to ¼ of itself gives 15.

Thus, this problem can be represented as given above:

`x + (1)/(4)x = 15`

Solve for x

`x + (x)/(4) = 15`

`(4x + x)/(4) = 15`

`(5x)/(4) = 15`

Multiply both sides by 4

`(5x)/(4)*4 = 15*4`

`5x = 60`

Divide both sides by 5

`(5x)/(5) = (60)/(5)`

`x = 12`