232k views
2 votes
Damon was on his way to a marble tournament when he met Artemio. Damon's bag of marbles was heavy, so he gave Artemio ½ of his marbles plus 2. Then he met Banou and gave her ¼ of his remaining marbles plus 5. Just before arriving at the tournament, he met Alex and gave him ½ of the marbles he had left. When he got to the tournament, he had 2 marbles left. How many marbles did he start with?

User Zeppomedio
by
8.5k points

1 Answer

3 votes

Answer: 28.

Explanation:

Let's define D = # of marbles in Damon's bag at the beginning.

First, he gave D/2 + 2 marbles to Artemio, so now he has:

(D - D/2 - 2) = (D/2 - 2) marbles left.

Now, he gives 1/4 plus of what he has left plus 5 to Banou, so he gives:

(D/2 - 2)/4 + 5 marbles to Banou.

Then Damon has now:

(D/2 - 2) - (D/2 - 2)/4 - 5 = 3*(D/2 - 2)/4 - 5.

Now Damon gives half of this to Alex, then the amount that he has left is:

(3*(D/2 - 2)/4 - 5)/2

And we know that this is equal to 2, then we can solve this equation as:

(3*(D/2 - 2)/4 - 5)/2 = 2

Let's solve this for D.

(3*(D/2 - 2)/4 - 5) = 2*2 = 4.

3*(D/2 - 2)/4 = 4 + 5 = 9

3*(D/2 - 2) = 9*4 = 36

(D/2 - 2) = 36/3 = 12

D/2 = 12 + 2 = 14

D = 2*14 = 28

Damon initially had 28 marbles.

User Victor Ashik
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories