Question

In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? In a two-slit experiment, the slit separation is 3.00 × 10-5 m. The interference pattern is created on a screen that is 2.00 m away from the slits. If the 7th bright fringe on the screen is a linear distance of 10.0 cm away from the central fringe, what is the wavelength of the light? 214 nm 224 nm 204 nm 100 nm 234 nm

Answer 1

The correct option is a: 214 nm.

Step-by-step explanation:

The wavelength (λ) of the light can be calculated as follows:

`\lambda = (yd)/(nD)` (1)

Where:

y: is the distance of the 7th bright fringe on the screen from the central fringe = 10.0 cm

d: is the distance between the slits = 3.00x10⁻⁵ m

D: is the distance between the screen and the slits = 2.00 m

n = 7

By entering all the above values into equation (1) we have:

`\lambda = (yd)/(nD) = (0.10 m*3.00 \cdot 10^(-5) m)/(7*2.00 m) = 214.3 nm`

Therefore, the correct option is a: 214 nm.

I hope it helps you!