Answer:
f(x) = x² + 2x - 3
(x+3)(x-1)
Explanation:
Zeroes are -3 and 1
Let α = -3 and β = 1
f(x) = x² - (α+β)x + (αβ)
= x² - (-3+1)x + (-3 × 1)
= x² - (-2)x + (-3)
= x² + 2x - 3
x²+2x-3
x² - x + 3x - 3
x(x-1) + 3(x-1)
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