Answer:
Something isn't right about this question, since Target's tolerance for stock-outs is already 1%, by how much can they decrease it? The question should probably say that they will increase their tolerance for stock-outs, e.g. from 1% to 5% or 10%.
currently, Target's safety stock is:
safety stock = z-score 99% x √lead time x standard deviation of demand
safety stock = 2.576 x √3 x 2 = 8.92 units ≈ 9 units
the reorder point = lead time demand + safety stock
lead time demand = 3 days x 5 = 15 units
reorder point = 15 + 9 = 24 units
Having a large safety stock and a high reorder point increases holding costs and may also increase the total number of orders placed per year.
If the tolerance for stock-outs increases to 5%, then the new safety stock is:
safety stock = z-score 95% x √lead time x standard deviation of demand
safety stock = 1.96 x √3 x 2 = 6.8 units ≈ 7 units
the reorder point will also decrease to 15 + 7 = 22 units
If the tolerance for stock-outs increases to 10%, then the new safety stock is:
safety stock = z-score 90% x √lead time x standard deviation of demand
safety stock = 1.645 x √3 x 2 = 5.7 units ≈ 6 units
the reorder point will also decrease to 15 + 6 = 21 units
The higher the tolerance for stock-outs, the lower the safety stock and reorder point, which in turn reduces carrying costs ($27.50 for every unit) and total number of orders ($10 per order).
If indeed, the question was properly written, then if target decreases its tolerance for stock-outs, the safety stock needed for a 0.5% tolerance is:
safety stock = z-score 99.5% x √lead time x standard deviation of demand
safety stock = 2.807 x √3 x 2 = 9.7 units ≈ 10 units
reorder point = 25 units
if the tolerance decreases to 0.01%:
safety stock = z-score 99.99% x √lead time x standard deviation of demand
safety stock = 3.891 x √3 x 2 = 13.4 units ≈ 13 units
reorder point = 28 units
The higher the safety stock and reorder point, the higher the carrying costs, more orders will be placed and the order costs will also be higher.