The length of CT is 39 .
Since J is the midpoint of CT, we know that CJ = JT.
Therefore, we can set the two expressions for CJ and JT equal to each other and solve for x:
2x - 1 = 82 - 43
2x = 40
x = 20
Now that we know x = 20, we can plug it back into either expression for CJ or JT to find the length of CT.
Let's plug it into the expression for CJ:
CJ = 2(20) - 1
CJ = 39
Therefore, the length of CT is 39.
Solution:
Since J is the midpoint of CT, we know that CJ = JT.
Therefore, we can set the two expressions for CJ and JT equal to each other and solve for x:
2x - 1 = 82 - 43
2x = 40
x = 20
Now that we know x = 20, we can plug it back into either expression for CJ or JT to find the length of CT.
Let's plug it into the expression for CJ:
CJ = 2(20) - 1
CJ = 39