Question

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9) Mount Everest is 8848 m above the sea level. Find the
acceleration due to gravity at this height. The value of
acceleration due to gravity at the earth's surface is 9.8 m/s2
and the radius of the earth is 6400km.​

Answer 1

Given parameters:

Height of Everest = 8848m

Acceleration due to gravity on earth = 9.8m/s²

Radius of the earth = 6400km = 6400000m

Unknown:

Acceleration due to gravity at the peak of Everest =?

Solution:

According to Newton's law of universal gravitation, we have that acceleration due to gravity is proportional to the altitude.

To solve this problem, use the mathematical expression below;

g
`_(e)` = g(1 -
`(2h)/(R)`)

where g
`_(e)` is gravity on top of Everest

g is the gravity on the earth surface

h is the height of the mountain

R is the radius of the earth

g
`_(e)` = 9.8 (1 -
`(2 x 8848)/(6400000)` )

g
`_(e)` = 9.8 (1-0.002765) = 9.77m/s²

The acceleration due to on top of Everest is 9.77m/s²