Question

What is the equation of the line that passes through the point (-2,0) and has a slope of -2

Answer 1

y=mx+c

we will find c

0=(-2)(-2)+c

c=-4

y=-2x+(-4)

y=-2x-4

2x+y+4=0

Answer 2

y = -2x -4

Explanation:

The equation of a line is y = mx + b, where m is the slope of the line, and b is the y-intercept. We are told that the slope of the line is -2, so we can start with

y = mx + b

y = -2x + b

We can figure out the value of b by plugging in the coordinates of the point given (-2, 0)

0 = -2(-2) + b

0 = 4 + b

Subtract 4 from both sides of the equation

-4 = b

Then plug that value of b back into the equation above:

y = -2x + (-4) or y = -2x -4