Answer:
(-2,-4)
Explanation:
3x-2y=2---eqn1
5x-5y=10---eqn2
multiply eqn1 by 5 and eqn2 by 2
5(3x-2y=2)
2(5x-5y=10)
15x-10y=10---eqn3
10x-10y=20---eqn4
Now subtract eqn4 from eqn3
5x=-10
x=-2
Plug x=-2 into eqn1
3(-2)-2y=2
-6-2y=2
-6-2=2y
-8=2y
y=-4
Therefore the answer is (-2,-4)