Question

What is an equation of the line that passes through the points (0, -5) and
(-5,-1)?

Answer 1

we find first slope

m=(-5+1)/(0+5)

m=-4/5

y-y1=m(x-x1)

y+ 5=(-4/5)(x-0)

5y+25=-4x

so equation is. 4x+5y+25=0

Answer 2

y=
`-(4)/(5)`x-5

Explanation:

The coordinates (0,-5) tells us the y intercept of the line, which is -5.

To find the equation of the line, we have to use the equation
`m=(y2-y1)/(x2-x1)` to find the slope of the line. Plug in the values of the other coordinates (-5,-1) into the equation, which would then leave you with :

m=
`((-1)-(-5))/((-5)-0)`

we then solve for m(the slope) and we get:

m=
`-(4)/(5)`

so the equation of the line is y=
`-(4)/(5)`x-5