Answer:
Explanation:
1+2/3m+2=2+1/6
We move all terms to the left:
1+2/3m+2-(2+1/6)=0
Domain of the equation: 3m!=0
m!=0/3
m!=0
m∈R
We add all the numbers together, and all the variables
2/3m+1+2-(1/6+2)=0
We add all the numbers together, and all the variables
2/3m+3-(1/6+2)=0
We get rid of parentheses
2/3m+3-2-1/6=0
We calculate fractions
There is no solution for this equation