Question

5.) Scott pushes a piano along a slope and has an initial velocity of 10.0 m/s [up]. Its acceleration is 2.0 m/s2 [down].

a.) After its release, what is the piano’s velocity at 2.0 s, 5.0 s and 8.0s? b.) What is the piano’s displacement at 2.0 s, 5.0 s and 8.0s?

Answer 1

a) 6m/s, 0m/s, -6m/s

b) 16m, 25m, 16m

Step-by-step explanation:

For the first part of the problem, use the Kinematic Equation for Final Velocity:

V = Vi + at

You are looking for the final velocities of the times: 2s, 5s, and 8s (plug those in for t). We also know that the acceleration is going down so it is negative (-2 is plugged in for a). 10 is the initial velocity and it is positive.

For the second part of the problem, use the Kinematic Equation for Displacement:

ΔX = Vi(t) + 1/2a(t²)

You are looking for the displacement of the piano at times: 2s, 5s, and 8s (plug in and square at t). Again, the acceleration is negative because it is in the direction of down, so plug -2 in for a. The initial velocity is positive 10. Plugging those numbers in for each variable should get the correct answer.

Hopefully this helped, I went on here in search of an answer and found it out myself and since no one has answered it yet, I'll help someone else out.