Question

Activity

Blaine is selling tickets to a rock concert. Tickets in the front section cost $60 each. Tickets in the back section cost $40
each. Blaine has 55 tickets left to sell, and to meet his sales quota he needs to sell more than $600 in tickets from the
remaining tickets.
Blaine makes a profit of $40 on every ticket for the front section. He makes a profit of $25 on every ticket for the back
section. What's the maximum profit Blaine can make from selling his remaining tickets?
You may find it helpful to review the steps of linear programming e.
Part A
Write the system of inequalities for the given situation where x represents the number of front section tickets and y
represents the number of back section tickets.

Answer 1

25 tickets more

Explanation:

Answer 2

I got x+y is (less than or equal to) 55 for the first inequality and 60x+40y>600 for the second one!

Explanation:

Since Blaine can sell a maximum of 55 tickets, the first inequalitly is x+y is less than OR EQUAL TO 55. Since the tickets in the back section cost $40 each, 40y represents the money made from those tickets. Blaine needs to make 600 in sale so the inequality is 60x+40y>600.