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Line M passes through points (2,-5) and (4, -3). Line N passes through points (-4, -8) and (-6,-6). Are lines M and N perpendicular? Explain.

A. No, the lines are not perpendicular because the product of their slopes equals -1.

B. Yes, the lines are perpendicular because the product of their slopes equals-1.

C. No, their lines are not perpendicular because the product of their slopes does not equal-1.

D. Yes, the lines are perpendicular because the product of their slopes does not equal -1.

User Moshtaf
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1 Answer

3 votes

Answer:

Yes, the lines are perpendicular because the product of their slopes equals -1 ⇒ B

Explanation:

The product of the slopes of the perpendicular lines is -1

So to prove that the lines are perpendicular let us find their slopes

The rule of the slope is:


m=(y2-y1)/(x2-x1) , where (x1, y1) and (x2, y2) are two points on the line

∵ Line M passes through points (2, -5) and (4, -3)

∴ x1 = 2 and x2 = 4

∴ y1 = -5 and y2 = -3

→ By using the rule of the slope above


m=(-3-(-5))/(4-2)=(-3+5)/(2)=(2)/(2)

The slope of line M is 1

∵ Line N passes through points (-4, -8) and (-6, -6)

∴ x1 = -4 and x2 = -6

∴ y1 = -8 and y2 = -6

→ By using the rule of the slope above


m=(-6-(-8))/(-6-(-4))=(-6+8)/(-6+4)=(2)/(-2)

The slope of line N is -1

1 × -1 = -1

∴ The product of the slopes of lines M and N is -1

∴ Lines M and N are perpendicular

Yes, the lines are perpendicular because the product of their

slopes equals -1.

User Luissimo
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6.1k points