Question

What is the value of BC in the given triangle?

Answer 1

BC = 1.2, Option B

Explanation:

1). Apply Law of Cosine:
`c^2=a^2+b^2-2ab\cdot cos(\gamma)`

`BC^2=AB^2+AC^2-2\cdot AB\cdot AC\cdot cos(\angle\ BAC)`

`AB=2\\AC=1\\\angle BAC=25`

2).
`BC^2=2^2+1^2-2\cdot 1\cdot cos(25)`

`BC=1.17`