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Determine the range of the function.

y=1/4x^2 - 5



a.All real numbers.

b.All integers less than or equal to -5.

c.All integers greater than or equal to -5.

d.All real numbers greater than or equal to -5.

1 Answer

1 vote

Answer:


Solution: f(x)\ge-5\\Interval:[-5,\infty)

Explanation:

Equation:
(1)/(4) x^2-5 = y

1).
(1)/(4) x^2-5 = y
(x^2)/(4)-5=y

2).
(x^2)/(4)-5=y
a=(1)/(4), b=0, c=-5

3).
x_v=-(b)/(2a)


=-(0)/(2((1)/(4)))


=0

4). now plug
x_v into
y_v


y_v=(0^2)/(4)-5


=-5

5). Minimum (0,-5) ∴
f(x)\ge-5

User Thomas Rbt
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