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It takes 77.4 N to push a 43.8 kg crate at a constant speed across flat ground. What is the coefficient of kinetic friction? (No unit)
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4 votes
It takes 77.4 N to push a 43.8 kg

crate at a constant speed across
flat ground. What is the
coefficient of kinetic friction?
(No unit)

User SMaZ
by
4.4k points

2 Answers

5 votes

.180 is indeed the correct answer for acellus

User LeeWay
by
4.9k points
0 votes

Answer:

0.180

Step-by-step explanation:

(Applied Force) / (Weight) = Coefficient of kinetic friction

(77.4 N) / (43.8 kg * 9.81 m/s/s) = 0.180

User Goga Koreli
by
5.3k points
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