Question

In squash, yellow seeds are dominant over green seeds. If two heterozygous yellow seed squash were crossed, what are the genotype and phenotype results? (Your "work" should show THREE things - the completed Punnett square, the possible genotypes, and possible phenotypes.)

Answer 1

The result of cross two squashes with yellow seeds is an offspring of squash with green seeds -dominant caracter- heterozygous and yellow seeds squashes in a genotype proportion 1:2:1 and phenotype proportion 3:1

Step-by-step explanation:

The cross of two heterozygous individuals for a characteristic results in an offspring that will have both characteristics in pure and heterozygous form. It is a cross monohybrid which complies with the principle of independent segregation exposed by Mendel.

For the characteristic "seed color" the green color would be G and yellow represented as g.

At the cross of two heterozygous squashs:

- Parents: Gg X Gg

- Punnett's Square:

Alleles G g

G GG Gg

g Gg gg

Offspring:

• A pumpkin of green seeds GG (25%)
• Two pumpkins of green heterozygous seeds Gg (50%)
• One pumpkin of yellow seeds gg (25%)

Genotype proportion 1:2:1

Phenotype proportion 3:1